What are the solutions to the equation 6x^2+31x+35=0 ?

The solutions to the equation 6x^2+31x+35=0 are x=-5/3 ,x=-7/2

Find the zeros of 6x^2+31x+35=0

The zeros of 6x^2+31x+35=0 are x=-5/3 ,x=-7/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 31 x + 35 = 0

x = - \frac{5}{3}, x = - \frac{7}{2}

Decimal Notation

x = - 1.66666 \dots, x = - 3.5

Solution steps

6 x^{2} + 31 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 31 \pm 3 1 ^{2} - 4 \cdot 6 \cdot 35}{2 \cdot 6}

3 1^{2} - 4 \cdot 6 \cdot 35 = 11

x_{1, 2} = \frac{- 31 \pm 11}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 31 + 11}{2 \cdot 6}, x_{2} = \frac{- 31 - 11}{2 \cdot 6}

x = \frac{- 31 + 11}{2 \cdot 6} : - \frac{5}{3}

x = \frac{- 31 - 11}{2 \cdot 6} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{3}, x = - \frac{7}{2}

(a + 3) (a - 5) = 5

x^{2} = 1 + x - x^{2}

- 2 x^{2} - 8 x - 5 = 0

x^{2} - 21 x + 54 = 0

a = 6 s^{2}

What are the solutions to the equation 6x^2+31x+35=0 ?
The solutions to the equation 6x^2+31x+35=0 are x=-5/3 ,x=-7/2
Find the zeros of 6x^2+31x+35=0
The zeros of 6x^2+31x+35=0 are x=-5/3 ,x=-7/2