What are the solutions to the equation x^2-21x+54=0 ?

The solutions to the equation x^2-21x+54=0 are x=18,x=3

Find the zeros of x^2-21x+54=0

The zeros of x^2-21x+54=0 are x=18,x=3

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x^{2} - 21 x + 54 = 0

x = 18, x = 3

Solution steps

x^{2} - 21 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 1 \cdot 54}{2 \cdot 1}

(- 21)^{2} - 4 \cdot 1 \cdot 54 = 15

x_{1, 2} = \frac{- ( - 21 ) \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 15}{2 \cdot 1}, x_{2} = \frac{- ( - 21 ) - 15}{2 \cdot 1}

x = \frac{- ( - 21 ) + 15}{2 \cdot 1} : 18

x = \frac{- ( - 21 ) - 15}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 18, x = 3

a = 6 s^{2}

- 46 = 17 - c^{2}

x^{2} + x - 1 = 0

7 p^{2} = p^{2} - 4 p

x, x^{2} + y^{2} + 2 = 0

What are the solutions to the equation x^2-21x+54=0 ?
The solutions to the equation x^2-21x+54=0 are x=18,x=3
Find the zeros of x^2-21x+54=0
The zeros of x^2-21x+54=0 are x=18,x=3