What are the solutions to the equation 7p^2=p^2-4p ?

The solutions to the equation 7p^2=p^2-4p are p=-2/3 ,p=0

Find the zeros of 7p^2=p^2-4p

The zeros of 7p^2=p^2-4p are p=-2/3 ,p=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 p^{2} = p^{2} - 4 p

p = - \frac{2}{3}, p = 0

Decimal

p = - 0.66666 \dots, p = 0

Solution steps

7 p^{2} = p^{2} - 4 p

Switch sides

p^{2} - 4 p = 7 p^{2}

Move

7 p^{2}

to the left side

- 6 p^{2} - 4 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 6 ) \cdot 0}{2 ( - 6 )}

(- 4)^{2} - 4 (- 6) \cdot 0 = 4

p_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 ( - 6 )}

Separate the solutions

p_{1} = \frac{- ( - 4 ) + 4}{2 ( - 6 )}, p_{2} = \frac{- ( - 4 ) - 4}{2 ( - 6 )}

p = \frac{- ( - 4 ) + 4}{2 ( - 6 )} : - \frac{2}{3}

p = \frac{- ( - 4 ) - 4}{2 ( - 6 )} : 0

The solutions to the quadratic equation are:

p = - \frac{2}{3}, p = 0

x, x^{2} + y^{2} + 2 = 0

15 x^{2} + 23 x + 4 = 0

9 (9 - 9 x^{2}) = 9

2 4^{2} + b^{2} = 4 0^{2}

2 x = 4 x^{2} - 1

What are the solutions to the equation 7p^2=p^2-4p ?
The solutions to the equation 7p^2=p^2-4p are p=-2/3 ,p=0
Find the zeros of 7p^2=p^2-4p
The zeros of 7p^2=p^2-4p are p=-2/3 ,p=0