What are the solutions to the equation solvefor x,f=2x^2-2y ?

The solutions to the equation solvefor x,f=2x^2-2y are x=sqrt((f+2y)/2),x=-sqrt((f+2y)/2)

Find the zeros of solvefor x,f=2x^2-2y

The zeros of solvefor x,f=2x^2-2y are x=sqrt((f+2y)/2),x=-sqrt((f+2y)/2)

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solve for

x, f = 2 x^{2} - 2 y

x = \frac{f + 2 y}{2}, x = - \frac{f + 2 y}{2}

Solution steps

f = 2 x^{2} - 2 y

Switch sides

2 x^{2} - 2 y = f

Move

2 y

to the right side

2 x^{2} = f + 2 y

Divide both sides by

2

x^{2} = \frac{f + 2 y}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{f + 2 y}{2}, x = - \frac{f + 2 y}{2}

- 16 t^{2} + 1600 = 0

8 (3 x^{2} + 4) = 0

x, x^{2} - x y + y^{2} = 27

4 (x^{2} - 1) = 2 (2 x + 1) - 3

3 x^{2} + 3 x

What are the solutions to the equation solvefor x,f=2x^2-2y ?
The solutions to the equation solvefor x,f=2x^2-2y are x=sqrt((f+2y)/2),x=-sqrt((f+2y)/2)
Find the zeros of solvefor x,f=2x^2-2y
The zeros of solvefor x,f=2x^2-2y are x=sqrt((f+2y)/2),x=-sqrt((f+2y)/2)