What are the solutions to the equation 8(3x^2+4)=0 ?

The solutions to the equation 8(3x^2+4)=0 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i

Find the zeros of 8(3x^2+4)=0

The zeros of 8(3x^2+4)=0 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i

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8 (3 x^{2} + 4) = 0

x = \frac{2}{3} i, x = - \frac{2}{3} i

Solution steps

8 (3 x^{2} + 4) = 0

Divide both sides by

8

3 x^{2} + 4 = 0

Move

4

to the right side

3 x^{2} = - 4

Divide both sides by

3

x^{2} = - \frac{4}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{4}{3}, x = - - \frac{4}{3}

- \frac{4}{3} = \frac{2}{3} i

- - \frac{4}{3} = - \frac{2}{3} i

x = \frac{2}{3} i, x = - \frac{2}{3} i

x, x^{2} - x y + y^{2} = 27

4 (x^{2} - 1) = 2 (2 x + 1) - 3

3 x^{2} + 3 x

4 x^{2} - 5 x = - 2

8 x^{2} + 12 x - 3 = 0

What are the solutions to the equation 8(3x^2+4)=0 ?
The solutions to the equation 8(3x^2+4)=0 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i
Find the zeros of 8(3x^2+4)=0
The zeros of 8(3x^2+4)=0 are x= 2/(sqrt(3))i,x=-2/(sqrt(3))i