What are the solutions to the equation 4x^2-5x=-2 ?

The solutions to the equation 4x^2-5x=-2 are x= 5/8+i(sqrt(7))/8 ,x= 5/8-i(sqrt(7))/8

Find the zeros of 4x^2-5x=-2

The zeros of 4x^2-5x=-2 are x= 5/8+i(sqrt(7))/8 ,x= 5/8-i(sqrt(7))/8

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4 x^{2} - 5 x = - 2

x = \frac{5}{8} + i \frac{7}{8}, x = \frac{5}{8} - i \frac{7}{8}

Solution steps

4 x^{2} - 5 x = - 2

Move

2

to the left side

4 x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

Simplify

(- 5)^{2} - 4 \cdot 4 \cdot 2 : 7 i

x_{1, 2} = \frac{- ( - 5 ) \pm 7 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7 i}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 7 i}{2 \cdot 4}

x = \frac{- ( - 5 ) + 7 i}{2 \cdot 4} : \frac{5}{8} + i \frac{7}{8}

x = \frac{- ( - 5 ) - 7 i}{2 \cdot 4} : \frac{5}{8} - i \frac{7}{8}

The solutions to the quadratic equation are:

x = \frac{5}{8} + i \frac{7}{8}, x = \frac{5}{8} - i \frac{7}{8}

8 x^{2} + 12 x - 3 = 0

2 x^{2} = 7 x - 6

5 w^{2} = - 15 w

(1 - x)^{2} = 4

m^{2} + 7 m = 0

What are the solutions to the equation 4x^2-5x=-2 ?
The solutions to the equation 4x^2-5x=-2 are x= 5/8+i(sqrt(7))/8 ,x= 5/8-i(sqrt(7))/8
Find the zeros of 4x^2-5x=-2
The zeros of 4x^2-5x=-2 are x= 5/8+i(sqrt(7))/8 ,x= 5/8-i(sqrt(7))/8