What are the solutions to the equation -16t^2-55t+10=0 ?

The solutions to the equation -16t^2-55t+10=0 are t=-(55+sqrt(3665))/(32),t=(sqrt(3665)-55)/(32)

Find the zeros of -16t^2-55t+10=0

The zeros of -16t^2-55t+10=0 are t=-(55+sqrt(3665))/(32),t=(sqrt(3665)-55)/(32)

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- 16 t^{2} - 55 t + 10 = 0

t = - \frac{55 + 3665}{32}, t = \frac{3665 - 55}{32}

Decimal Notation

t = - 3.61060 \dots, t = 0.17310 \dots

Solution steps

- 16 t^{2} - 55 t + 10 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 55 ) \pm ( - 55 ) ^{2} - 4 ( - 16 ) \cdot 10}{2 ( - 16 )}

(- 55)^{2} - 4 (- 16) \cdot 10 = 3665

t_{1, 2} = \frac{- ( - 55 ) \pm 3665}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- ( - 55 ) + 3665}{2 ( - 16 )}, t_{2} = \frac{- ( - 55 ) - 3665}{2 ( - 16 )}

t = \frac{- ( - 55 ) + 3665}{2 ( - 16 )} : - \frac{55 + 3665}{32}

t = \frac{- ( - 55 ) - 3665}{2 ( - 16 )} : \frac{3665 - 55}{32}

The solutions to the quadratic equation are:

t = - \frac{55 + 3665}{32}, t = \frac{3665 - 55}{32}

105 = x - 2 x^{2}

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(1 - x)^{2} + 1 = 0

x^{2} + 2 x + 0.5 = 0

x^{2} - 21 x + 80 = 0

What are the solutions to the equation -16t^2-55t+10=0 ?
The solutions to the equation -16t^2-55t+10=0 are t=-(55+sqrt(3665))/(32),t=(sqrt(3665)-55)/(32)
Find the zeros of -16t^2-55t+10=0
The zeros of -16t^2-55t+10=0 are t=-(55+sqrt(3665))/(32),t=(sqrt(3665)-55)/(32)