What are the solutions to the equation (1-x)^2+1=0 ?

The solutions to the equation (1-x)^2+1=0 are x=-i+1,x=i+1

Find the zeros of (1-x)^2+1=0

The zeros of (1-x)^2+1=0 are x=-i+1,x=i+1

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(1 - x)^{2} + 1 = 0

x = - i + 1, x = i + 1

Solution steps

(1 - x)^{2} + 1 = 0

Move

1

to the right side

(1 - x)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 - x = - 1 : x = - i + 1

Solve

1 - x = - - 1 : x = i + 1

The solutions to the quadratic equation are:

x = - i + 1, x = i + 1

x^{2} + 2 x + 0.5 = 0

x^{2} - 21 x + 80 = 0

4 x^{2} - 7 = 9

- x^{2} - 2 x + 58 = 3 x + 22

- t^{2} + 70 t + 460 = 1516

What are the solutions to the equation (1-x)^2+1=0 ?
The solutions to the equation (1-x)^2+1=0 are x=-i+1,x=i+1
Find the zeros of (1-x)^2+1=0
The zeros of (1-x)^2+1=0 are x=-i+1,x=i+1