What are the solutions to the equation -x^2-2x+58=3x+22 ?

The solutions to the equation -x^2-2x+58=3x+22 are x=-9,x=4

Find the zeros of -x^2-2x+58=3x+22

The zeros of -x^2-2x+58=3x+22 are x=-9,x=4

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- x^{2} - 2 x + 58 = 3 x + 22

x = - 9, x = 4

Solution steps

- x^{2} - 2 x + 58 = 3 x + 22

Move

22

to the left side

- x^{2} - 2 x + 36 = 3 x

Move

3 x

to the left side

- x^{2} - 5 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 1 ) \cdot 36}{2 ( - 1 )}

(- 5)^{2} - 4 (- 1) \cdot 36 = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 ( - 1 )}, x_{2} = \frac{- ( - 5 ) - 13}{2 ( - 1 )}

x = \frac{- ( - 5 ) + 13}{2 ( - 1 )} : - 9

x = \frac{- ( - 5 ) - 13}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = - 9, x = 4

- t^{2} + 70 t + 460 = 1516

10 x - x^{2} = 0

3 (x + 2)^{2} - 11 = 25

10 x^{2} - 8 x - 2 = 0

10 x^{2} - 9 x = - 5 x^{2} + 11 x

What are the solutions to the equation -x^2-2x+58=3x+22 ?
The solutions to the equation -x^2-2x+58=3x+22 are x=-9,x=4
Find the zeros of -x^2-2x+58=3x+22
The zeros of -x^2-2x+58=3x+22 are x=-9,x=4