What are the solutions to the equation 10x^2-9x=-5x^2+11x ?

The solutions to the equation 10x^2-9x=-5x^2+11x are x= 4/3 ,x=0

Find the zeros of 10x^2-9x=-5x^2+11x

The zeros of 10x^2-9x=-5x^2+11x are x= 4/3 ,x=0

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10 x^{2} - 9 x = - 5 x^{2} + 11 x

x = \frac{4}{3}, x = 0

Decimal Notation

x = 1.33333 \dots, x = 0

Solution steps

10 x^{2} - 9 x = - 5 x^{2} + 11 x

Move

11 x

to the left side

10 x^{2} - 20 x = - 5 x^{2}

Move

5 x^{2}

to the left side

15 x^{2} - 20 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 15 \cdot 0}{2 \cdot 15}

(- 20)^{2} - 4 \cdot 15 \cdot 0 = 20

x_{1, 2} = \frac{- ( - 20 ) \pm 20}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 20}{2 \cdot 15}, x_{2} = \frac{- ( - 20 ) - 20}{2 \cdot 15}

x = \frac{- ( - 20 ) + 20}{2 \cdot 15} : \frac{4}{3}

x = \frac{- ( - 20 ) - 20}{2 \cdot 15} : 0

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = 0

j (x) = x^{2}

2 x^{2} + 2 x = 6

2 x^{2} + 2 x = 3

x^{2} + 10 x + 70 = 0

2 x (2 x + 1) - 10 x - 16 = 5 x^{2}

What are the solutions to the equation 10x^2-9x=-5x^2+11x ?
The solutions to the equation 10x^2-9x=-5x^2+11x are x= 4/3 ,x=0
Find the zeros of 10x^2-9x=-5x^2+11x
The zeros of 10x^2-9x=-5x^2+11x are x= 4/3 ,x=0