What are the solutions to the equation 9z^2-49=0 ?

The solutions to the equation 9z^2-49=0 are z= 7/3 ,z=-7/3

Find the zeros of 9z^2-49=0

The zeros of 9z^2-49=0 are z= 7/3 ,z=-7/3

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9 z^{2} - 49 = 0

z = \frac{7}{3}, z = - \frac{7}{3}

Decimal Notation

z = 2.33333 \dots, z = - 2.33333 \dots

Solution steps

9 z^{2} - 49 = 0

Move

49

to the right side

9 z^{2} = 49

Divide both sides by

9

z^{2} = \frac{49}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = \frac{49}{9}, z = - \frac{49}{9}

\frac{49}{9} = \frac{7}{3}

- \frac{49}{9} = - \frac{7}{3}

z = \frac{7}{3}, z = - \frac{7}{3}

9 x^{2} = 42 x - 50

(3 x + 1) (x + 5) = 0

5582.28 x^{2} + 81.42 x = 43200

x^{2} - 3 = 2 x - 4 x^{2} + 6

9 x^{2} + 32 = 3 x^{2} + 86

What are the solutions to the equation 9z^2-49=0 ?
The solutions to the equation 9z^2-49=0 are z= 7/3 ,z=-7/3
Find the zeros of 9z^2-49=0
The zeros of 9z^2-49=0 are z= 7/3 ,z=-7/3