What are the solutions to the equation 28=y^2 ?

The solutions to the equation 28=y^2 are y=2sqrt(7),y=-2sqrt(7)

Find the zeros of 28=y^2

The zeros of 28=y^2 are y=2sqrt(7),y=-2sqrt(7)

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28 = y^{2}

y = 27, y = - 27

Decimal Notation

y = 5.29150 \dots, y = - 5.29150 \dots

Solution steps

28 = y^{2}

Switch sides

y^{2} = 28

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 28, y = - 28

28 = 27

- 28 = - 27

y = 27, y = - 27

0 = x^{2} - 6 x + 7

2 x^{2} = 10 x - 11

5 x^{2} = 25 x

3 x^{2} + 12 x + 13 = 0

y^{2} = 169

What are the solutions to the equation 28=y^2 ?
The solutions to the equation 28=y^2 are y=2sqrt(7),y=-2sqrt(7)
Find the zeros of 28=y^2
The zeros of 28=y^2 are y=2sqrt(7),y=-2sqrt(7)