What are the solutions to the equation solvefor x,3(2x+5)^2=90 ?

The solutions to the equation solvefor x,3(2x+5)^2=90 are x=(sqrt(30)-5)/2 ,x=(-sqrt(30)-5)/2

Find the zeros of solvefor x,3(2x+5)^2=90

The zeros of solvefor x,3(2x+5)^2=90 are x=(sqrt(30)-5)/2 ,x=(-sqrt(30)-5)/2

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solve for

x, 3 (2 x + 5)^{2} = 90

x = \frac{30 - 5}{2}, x = \frac{- 30 - 5}{2}

Decimal Notation

x = 0.23861 \dots, x = - 5.23861 \dots

Solution steps

3 (2 x + 5)^{2} = 90

Divide both sides by

3

(2 x + 5)^{2} = 30

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 5 = 30 : x = \frac{30 - 5}{2}

Solve

2 x + 5 = - 30 : x = \frac{- 30 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{30 - 5}{2}, x = \frac{- 30 - 5}{2}

(x - 10) (3 x + 2) = 0

x^{2} + 7 x = 18

u^{2} + 8 u

- 3 x^{2} + 7 x + 2 = 0

u^{2} + 2 u

What are the solutions to the equation solvefor x,3(2x+5)^2=90 ?
The solutions to the equation solvefor x,3(2x+5)^2=90 are x=(sqrt(30)-5)/2 ,x=(-sqrt(30)-5)/2
Find the zeros of solvefor x,3(2x+5)^2=90
The zeros of solvefor x,3(2x+5)^2=90 are x=(sqrt(30)-5)/2 ,x=(-sqrt(30)-5)/2