What are the solutions to the equation -3x^2+7x+2=0 ?

The solutions to the equation -3x^2+7x+2=0 are x=-(-7+sqrt(73))/6 ,x=(7+sqrt(73))/6

Find the zeros of -3x^2+7x+2=0

The zeros of -3x^2+7x+2=0 are x=-(-7+sqrt(73))/6 ,x=(7+sqrt(73))/6

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- 3 x^{2} + 7 x + 2 = 0

x = - \frac{- 7 + 73}{6}, x = \frac{7 + 73}{6}

Decimal Notation

x = - 0.25733 \dots, x = 2.59066 \dots

Solution steps

- 3 x^{2} + 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 3 ) \cdot 2}{2 ( - 3 )}

7^{2} - 4 (- 3) \cdot 2 = 73

x_{1, 2} = \frac{- 7 \pm 73}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 7 + 73}{2 ( - 3 )}, x_{2} = \frac{- 7 - 73}{2 ( - 3 )}

x = \frac{- 7 + 73}{2 ( - 3 )} : - \frac{- 7 + 73}{6}

x = \frac{- 7 - 73}{2 ( - 3 )} : \frac{7 + 73}{6}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 73}{6}, x = \frac{7 + 73}{6}

u^{2} + 2 u

x^{2} + 19 x + 3 = - 10

6 x^{2} - 6 x = - 1

x^{2} + 13 x - 7 = 0

x^{2} + 8 x + 25

What are the solutions to the equation -3x^2+7x+2=0 ?
The solutions to the equation -3x^2+7x+2=0 are x=-(-7+sqrt(73))/6 ,x=(7+sqrt(73))/6
Find the zeros of -3x^2+7x+2=0
The zeros of -3x^2+7x+2=0 are x=-(-7+sqrt(73))/6 ,x=(7+sqrt(73))/6