What are the solutions to the equation 6x^2-6x=-1 ?

The solutions to the equation 6x^2-6x=-1 are x=(3+sqrt(3))/6 ,x=(3-sqrt(3))/6

Find the zeros of 6x^2-6x=-1

The zeros of 6x^2-6x=-1 are x=(3+sqrt(3))/6 ,x=(3-sqrt(3))/6

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6 x^{2} - 6 x = - 1

x = \frac{3 + 3}{6}, x = \frac{3 - 3}{6}

Decimal Notation

x = 0.78867 \dots, x = 0.21132 \dots

Solution steps

6 x^{2} - 6 x = - 1

Move

1

to the left side

6 x^{2} - 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 6 \cdot 1}{2 \cdot 6}

(- 6)^{2} - 4 \cdot 6 \cdot 1 = 23

x_{1, 2} = \frac{- ( - 6 ) \pm 2 3}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 3}{2 \cdot 6}, x_{2} = \frac{- ( - 6 ) - 2 3}{2 \cdot 6}

x = \frac{- ( - 6 ) + 2 3}{2 \cdot 6} : \frac{3 + 3}{6}

x = \frac{- ( - 6 ) - 2 3}{2 \cdot 6} : \frac{3 - 3}{6}

The solutions to the quadratic equation are:

x = \frac{3 + 3}{6}, x = \frac{3 - 3}{6}

x^{2} + 13 x - 7 = 0

x^{2} + 8 x + 25

(x + 3) (x + 9) = 0

0 = \frac{1}{2} (3 - x) (2 - x)

2 x^{2} + 10 x = 12

What are the solutions to the equation 6x^2-6x=-1 ?
The solutions to the equation 6x^2-6x=-1 are x=(3+sqrt(3))/6 ,x=(3-sqrt(3))/6
Find the zeros of 6x^2-6x=-1
The zeros of 6x^2-6x=-1 are x=(3+sqrt(3))/6 ,x=(3-sqrt(3))/6