What are the solutions to the equation 0= 1/2 (3-x)(2-x) ?

The solutions to the equation 0= 1/2 (3-x)(2-x) are x=3,x=2

Find the zeros of 0= 1/2 (3-x)(2-x)

The zeros of 0= 1/2 (3-x)(2-x) are x=3,x=2

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0 = \frac{1}{2} (3 - x) (2 - x)

x = 3, x = 2

Solution steps

0 = \frac{1}{2} (3 - x) (2 - x)

Switch sides

\frac{1}{2} (3 - x) (2 - x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 - x = 0 or 2 - x = 0

Solve

3 - x = 0 : x = 3

Solve

2 - x = 0 : x = 2

The solutions to the quadratic equation are:

x = 3, x = 2

2 x^{2} + 10 x = 12

x^{2} - 10 = 26

x^{2} - 10 = 39

n^{(2)} - 6 n + 13 = - 4

x^{2} - 14 x + 48 = - 10

What are the solutions to the equation 0= 1/2 (3-x)(2-x) ?
The solutions to the equation 0= 1/2 (3-x)(2-x) are x=3,x=2
Find the zeros of 0= 1/2 (3-x)(2-x)
The zeros of 0= 1/2 (3-x)(2-x) are x=3,x=2