What are the solutions to the equation n^{(2)}-6n+13=-4 ?

The solutions to the equation n^{(2)}-6n+13=-4 are n=3+2sqrt(2)i,n=3-2sqrt(2)i

Find the zeros of n^{(2)}-6n+13=-4

The zeros of n^{(2)}-6n+13=-4 are n=3+2sqrt(2)i,n=3-2sqrt(2)i

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n^{(2)} - 6 n + 13 = - 4

n = 3 + 22 i, n = 3 - 22 i

Solution steps

n^{(2)} - 6 n + 13 = - 4

Refine

n^{2} - 6 n + 13 = - 4

Move

4

to the left side

n^{2} - 6 n + 17 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 17 : 42 i

n_{1, 2} = \frac{- ( - 6 ) \pm 4 2 i}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 6 ) + 4 2 i}{2 \cdot 1}, n_{2} = \frac{- ( - 6 ) - 4 2 i}{2 \cdot 1}

n = \frac{- ( - 6 ) + 4 2 i}{2 \cdot 1} : 3 + 22 i

n = \frac{- ( - 6 ) - 4 2 i}{2 \cdot 1} : 3 - 22 i

The solutions to the quadratic equation are:

n = 3 + 22 i, n = 3 - 22 i

x^{2} - 14 x + 48 = - 10

2 x^{2} + 14 x - 120 = 0

6 x^{2} = 3 x - 9

x, \frac{x ^{2}}{2} + \frac{y ^{2}}{3} + \frac{z ^{2}}{4} = 1

x^{2} = e^{4}

What are the solutions to the equation n^{(2)}-6n+13=-4 ?
The solutions to the equation n^{(2)}-6n+13=-4 are n=3+2sqrt(2)i,n=3-2sqrt(2)i
Find the zeros of n^{(2)}-6n+13=-4
The zeros of n^{(2)}-6n+13=-4 are n=3+2sqrt(2)i,n=3-2sqrt(2)i