What are the solutions to the equation 4x^2-3x-9=0 ?

The solutions to the equation 4x^2-3x-9=0 are x=(3+3sqrt(17))/8 ,x=(3-3sqrt(17))/8

Find the zeros of 4x^2-3x-9=0

The zeros of 4x^2-3x-9=0 are x=(3+3sqrt(17))/8 ,x=(3-3sqrt(17))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 3 x - 9 = 0

x = \frac{3 + 3 17}{8}, x = \frac{3 - 3 17}{8}

Decimal Notation

x = 1.92116 \dots, x = - 1.17116 \dots

Solution steps

4 x^{2} - 3 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

(- 3)^{2} - 4 \cdot 4 (- 9) = 317

x_{1, 2} = \frac{- ( - 3 ) \pm 3 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 17}{2 \cdot 4}, x_{2} = \frac{- ( - 3 ) - 3 17}{2 \cdot 4}

x = \frac{- ( - 3 ) + 3 17}{2 \cdot 4} : \frac{3 + 3 17}{8}

x = \frac{- ( - 3 ) - 3 17}{2 \cdot 4} : \frac{3 - 3 17}{8}

The solutions to the quadratic equation are:

x = \frac{3 + 3 17}{8}, x = \frac{3 - 3 17}{8}

x^{2} - 8 x + 24 = 9

(2 x - 5) (x + 1) = 5

\frac{3}{1000} = \frac{1}{2} (0.005) (x - 3 - 0.5)^{2}

6 x^{2} - 20 x + 6 = 0

x^{2} - 3 x + 2 = 0

What are the solutions to the equation 4x^2-3x-9=0 ?
The solutions to the equation 4x^2-3x-9=0 are x=(3+3sqrt(17))/8 ,x=(3-3sqrt(17))/8
Find the zeros of 4x^2-3x-9=0
The zeros of 4x^2-3x-9=0 are x=(3+3sqrt(17))/8 ,x=(3-3sqrt(17))/8