What are the solutions to the equation x^2-8x+24=9 ?

The solutions to the equation x^2-8x+24=9 are x=5,x=3

Find the zeros of x^2-8x+24=9

The zeros of x^2-8x+24=9 are x=5,x=3

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x^{2} - 8 x + 24 = 9

x = 5, x = 3

Solution steps

x^{2} - 8 x + 24 = 9

Move

9

to the left side

x^{2} - 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

x_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

x = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 5, x = 3

(2 x - 5) (x + 1) = 5

\frac{3}{1000} = \frac{1}{2} (0.005) (x - 3 - 0.5)^{2}

6 x^{2} - 20 x + 6 = 0

x^{2} - 3 x + 2 = 0

x^{2} + 6 x + 9 = \frac{49}{4}

What are the solutions to the equation x^2-8x+24=9 ?
The solutions to the equation x^2-8x+24=9 are x=5,x=3
Find the zeros of x^2-8x+24=9
The zeros of x^2-8x+24=9 are x=5,x=3