What are the solutions to the equation x^2+6x+9= 49/4 ?

The solutions to the equation x^2+6x+9= 49/4 are x= 1/2 ,x=-13/2

Find the zeros of x^2+6x+9= 49/4

The zeros of x^2+6x+9= 49/4 are x= 1/2 ,x=-13/2

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x^{2} + 6 x + 9 = \frac{49}{4}

x = \frac{1}{2}, x = - \frac{13}{2}

Decimal Notation

x = 0.5, x = - 6.5

Solution steps

x^{2} + 6 x + 9 = \frac{49}{4}

Multiply both sides by

4

4 x^{2} + 24 x + 36 = 49

Move

49

to the left side

4 x^{2} + 24 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 ( - 13 )}{2 \cdot 4}

2 4^{2} - 4 \cdot 4 (- 13) = 28

x_{1, 2} = \frac{- 24 \pm 28}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 24 + 28}{2 \cdot 4}, x_{2} = \frac{- 24 - 28}{2 \cdot 4}

x = \frac{- 24 + 28}{2 \cdot 4} : \frac{1}{2}

x = \frac{- 24 - 28}{2 \cdot 4} : - \frac{13}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{13}{2}

\frac{1}{2} x^{2} - 12 = - 37

3 x^{2} - x + 17 = 17

2 x^{2} - 8 x - 64 = 0

\frac{3}{4} y^{2} - 3 = 18

5 v^{2} - 15 v = 0

What are the solutions to the equation x^2+6x+9= 49/4 ?
The solutions to the equation x^2+6x+9= 49/4 are x= 1/2 ,x=-13/2
Find the zeros of x^2+6x+9= 49/4
The zeros of x^2+6x+9= 49/4 are x= 1/2 ,x=-13/2