What are the solutions to the equation 4(x-5)^2+20=0 ?

The solutions to the equation 4(x-5)^2+20=0 are x=sqrt(5)i+5,x=-sqrt(5)i+5

Find the zeros of 4(x-5)^2+20=0

The zeros of 4(x-5)^2+20=0 are x=sqrt(5)i+5,x=-sqrt(5)i+5

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4 (x - 5)^{2} + 20 = 0

x = 5 i + 5, x = - 5 i + 5

Solution steps

4 (x - 5)^{2} + 20 = 0

Move

20

to the right side

4 (x - 5)^{2} = - 20

Divide both sides by

4

(x - 5)^{2} = - 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = - 5 : x = 5 i + 5

Solve

x - 5 = - - 5 : x = - 5 i + 5

The solutions to the quadratic equation are:

x = 5 i + 5, x = - 5 i + 5

1 = 5 x^{2} + 4 x

x^{2} + 14 x = 12

1 5^{2} + x^{2} = 2 0^{2}

(x - 6)^{2} = 44

7 v^{2} - 3 v = 0

What are the solutions to the equation 4(x-5)^2+20=0 ?
The solutions to the equation 4(x-5)^2+20=0 are x=sqrt(5)i+5,x=-sqrt(5)i+5
Find the zeros of 4(x-5)^2+20=0
The zeros of 4(x-5)^2+20=0 are x=sqrt(5)i+5,x=-sqrt(5)i+5