What are the solutions to the equation 7v^2-3v=0 ?

The solutions to the equation 7v^2-3v=0 are v= 3/7 ,v=0

Find the zeros of 7v^2-3v=0

The zeros of 7v^2-3v=0 are v= 3/7 ,v=0

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7 v^{2} - 3 v = 0

v = \frac{3}{7}, v = 0

Decimal Notation

v = 0.42857 \dots, v = 0

Solution steps

7 v^{2} - 3 v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 7 \cdot 0}{2 \cdot 7}

(- 3)^{2} - 4 \cdot 7 \cdot 0 = 3

v_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 7}

Separate the solutions

v_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 7}, v_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 7}

v = \frac{- ( - 3 ) + 3}{2 \cdot 7} : \frac{3}{7}

v = \frac{- ( - 3 ) - 3}{2 \cdot 7} : 0

The solutions to the quadratic equation are:

v = \frac{3}{7}, v = 0

3 x^{2} - 6 = 24

2 x - 3 = 1 - 2 x + x^{2}

(x + 3) (x - 3) = 27

30 + 40 x - 3 x^{2} = 0

\frac{1}{d ^{2}} = \frac{h ^{2} + k ^{2}}{a ^{2}} + \frac{l ^{2}}{c ^{2}}

What are the solutions to the equation 7v^2-3v=0 ?
The solutions to the equation 7v^2-3v=0 are v= 3/7 ,v=0
Find the zeros of 7v^2-3v=0
The zeros of 7v^2-3v=0 are v= 3/7 ,v=0