What are the solutions to the equation 5x^2+38x+21=(5x+3) ?

The solutions to the equation 5x^2+38x+21=(5x+3) are x=-3/5 ,x=-6

Find the zeros of 5x^2+38x+21=(5x+3)

The zeros of 5x^2+38x+21=(5x+3) are x=-3/5 ,x=-6

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5 x^{2} + 38 x + 21 = (5 x + 3)

x = - \frac{3}{5}, x = - 6

Decimal Notation

x = - 0.6, x = - 6

Solution steps

5 x^{2} + 38 x + 21 = (5 x + 3)

Refine

5 x^{2} + 38 x + 21 = 5 x + 3

Move

3

to the left side

5 x^{2} + 38 x + 18 = 5 x

Move

5 x

to the left side

5 x^{2} + 33 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 33 \pm 3 3 ^{2} - 4 \cdot 5 \cdot 18}{2 \cdot 5}

3 3^{2} - 4 \cdot 5 \cdot 18 = 27

x_{1, 2} = \frac{- 33 \pm 27}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 33 + 27}{2 \cdot 5}, x_{2} = \frac{- 33 - 27}{2 \cdot 5}

x = \frac{- 33 + 27}{2 \cdot 5} : - \frac{3}{5}

x = \frac{- 33 - 27}{2 \cdot 5} : - 6

The solutions to the quadratic equation are:

x = - \frac{3}{5}, x = - 6

7 = \frac{1}{12} x^{2} + \frac{2}{3} x

c^{2} + 5 (5 - c) = 22

3 x^{2} - 28 x + 56 = 7

2.25 x^{2} - 3 x = - 1

(x + 3)^{2} = 3 x

What are the solutions to the equation 5x^2+38x+21=(5x+3) ?
The solutions to the equation 5x^2+38x+21=(5x+3) are x=-3/5 ,x=-6
Find the zeros of 5x^2+38x+21=(5x+3)
The zeros of 5x^2+38x+21=(5x+3) are x=-3/5 ,x=-6