What are the solutions to the equation 0.5x(1-x/(500))-0.2x=0 ?

The solutions to the equation 0.5x(1-x/(500))-0.2x=0 are x=0,x=300

Find the zeros of 0.5x(1-x/(500))-0.2x=0

The zeros of 0.5x(1-x/(500))-0.2x=0 are x=0,x=300

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0.5 x (1 - \frac{x}{500}) - 0.2 x = 0

x = 0, x = 300

Solution steps

0.5 x (1 - \frac{x}{500}) - 0.2 x = 0

Multiply both sides by

10

5 x (1 - \frac{x}{500}) - 2 x = 0

Expand

5 x (1 - \frac{x}{500}) - 2 x : - \frac{x ^{2}}{100} + 3 x

- \frac{x ^{2}}{100} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - \frac{1}{100} ) \cdot 0}{2 ( - \frac{1}{100} )}

3^{2} - 4 (- \frac{1}{100}) \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 ( - \frac{1}{100} )}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 ( - \frac{1}{100} )}, x_{2} = \frac{- 3 - 3}{2 ( - \frac{1}{100} )}

x = \frac{- 3 + 3}{2 ( - \frac{1}{100} )} : 0

x = \frac{- 3 - 3}{2 ( - \frac{1}{100} )} : 300

The solutions to the quadratic equation are:

x = 0, x = 300

36 x^{2} - 60 x + 5 = 0

b^{2} - 49 = 0

x^{2} + \frac{10}{3} x + 1 = 0

x, 4 x^{2} - 64 x y - 44 y^{2} + 75 = 0

3 p^{2} + 6 p + 3 = 0

What are the solutions to the equation 0.5x(1-x/(500))-0.2x=0 ?
The solutions to the equation 0.5x(1-x/(500))-0.2x=0 are x=0,x=300
Find the zeros of 0.5x(1-x/(500))-0.2x=0
The zeros of 0.5x(1-x/(500))-0.2x=0 are x=0,x=300