What are the solutions to the equation 3p^2+6p+3=0 ?

The solutions to the equation 3p^2+6p+3=0 are p=-1

Find the zeros of 3p^2+6p+3=0

The zeros of 3p^2+6p+3=0 are p=-1

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3 p^{2} + 6 p + 3 = 0

p = - 1

Solution steps

3 p^{2} + 6 p + 3 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

6^{2} - 4 \cdot 3 \cdot 3 = 0

p_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 3}

p = \frac{- 6}{2 \cdot 3}

\frac{- 6}{2 \cdot 3} = - 1

p = - 1

The solution to the quadratic equation is:

p = - 1

(2 x - 3) (3 x + 1) = 0

d, d r d q = 392 (q + 7) 2

4 x^{2} - 72 x + 324 = 0

v^{2} + 15 v + 11 = 5 v + 5

x^{2} - 5 x + 6 x = 0

What are the solutions to the equation 3p^2+6p+3=0 ?
The solutions to the equation 3p^2+6p+3=0 are p=-1
Find the zeros of 3p^2+6p+3=0
The zeros of 3p^2+6p+3=0 are p=-1