What are the solutions to the equation -4x^2-4x+1=0 ?

The solutions to the equation -4x^2-4x+1=0 are x=-(1+sqrt(2))/2 ,x=(sqrt(2)-1)/2

Find the zeros of -4x^2-4x+1=0

The zeros of -4x^2-4x+1=0 are x=-(1+sqrt(2))/2 ,x=(sqrt(2)-1)/2

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- 4 x^{2} - 4 x + 1 = 0

x = - \frac{1 + 2}{2}, x = \frac{2 - 1}{2}

Decimal Notation

x = - 1.20710 \dots, x = 0.20710 \dots

Solution steps

- 4 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 4 ) \cdot 1}{2 ( - 4 )}

(- 4)^{2} - 4 (- 4) \cdot 1 = 42

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2}{2 ( - 4 )}, x_{2} = \frac{- ( - 4 ) - 4 2}{2 ( - 4 )}

x = \frac{- ( - 4 ) + 4 2}{2 ( - 4 )} : - \frac{1 + 2}{2}

x = \frac{- ( - 4 ) - 4 2}{2 ( - 4 )} : \frac{2 - 1}{2}

The solutions to the quadratic equation are:

x = - \frac{1 + 2}{2}, x = \frac{2 - 1}{2}

6 x^{2} - 8 x = 1

x, 2 x^{2} - 4 x y + 5 x = 10

x^{2} - 15 = - 15

2 x^{2} - 20 = 30

7 - 4 t + t^{2} = 0

What are the solutions to the equation -4x^2-4x+1=0 ?
The solutions to the equation -4x^2-4x+1=0 are x=-(1+sqrt(2))/2 ,x=(sqrt(2)-1)/2
Find the zeros of -4x^2-4x+1=0
The zeros of -4x^2-4x+1=0 are x=-(1+sqrt(2))/2 ,x=(sqrt(2)-1)/2