What are the solutions to the equation x-1=x^2-6x+9 ?

The solutions to the equation x-1=x^2-6x+9 are x=5,x=2

Find the zeros of x-1=x^2-6x+9

The zeros of x-1=x^2-6x+9 are x=5,x=2

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x - 1 = x^{2} - 6 x + 9

x = 5, x = 2

Solution steps

x - 1 = x^{2} - 6 x + 9

Switch sides

x^{2} - 6 x + 9 = x - 1

Move

1

to the left side

x^{2} - 6 x + 10 = x

Move

x

to the left side

x^{2} - 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

x_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

x = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

x = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 5, x = 2

3 v^{2} + 2 = - 2

3 x + (- 5 x (x + 3)) = 8 x + (- 5 x - 9)

- 6 x^{2} + 2 x - 4 = 9 x

(x + 3)^{2} = (x + 1)^{2} + (2 x)^{2}

3 x^{2} + 3 x - 9 = 0

What are the solutions to the equation x-1=x^2-6x+9 ?
The solutions to the equation x-1=x^2-6x+9 are x=5,x=2
Find the zeros of x-1=x^2-6x+9
The zeros of x-1=x^2-6x+9 are x=5,x=2