What are the solutions to the equation 3x^2+3x-9=0 ?

The solutions to the equation 3x^2+3x-9=0 are x=(-1+sqrt(13))/2 ,x=-(1+sqrt(13))/2

Find the zeros of 3x^2+3x-9=0

The zeros of 3x^2+3x-9=0 are x=(-1+sqrt(13))/2 ,x=-(1+sqrt(13))/2

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3 x^{2} + 3 x - 9 = 0

x = \frac{- 1 + 13}{2}, x = - \frac{1 + 13}{2}

Decimal Notation

x = 1.30277 \dots, x = - 2.30277 \dots

Solution steps

3 x^{2} + 3 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 9) = 313

x_{1, 2} = \frac{- 3 \pm 3 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 3 13}{2 \cdot 3}, x_{2} = \frac{- 3 - 3 13}{2 \cdot 3}

x = \frac{- 3 + 3 13}{2 \cdot 3} : \frac{- 1 + 13}{2}

x = \frac{- 3 - 3 13}{2 \cdot 3} : - \frac{1 + 13}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 13}{2}, x = - \frac{1 + 13}{2}

4 r^{2} + r + 2 = 0

x^{2} + 14 - x = - 10 x

x, x^{2} + 8 x - 9 = 0

x, 16 x^{2} - 96 x - 9 y^{2} + 18 y + 135 = 0

2 x^{2} + 5 x + 20 = 0

What are the solutions to the equation 3x^2+3x-9=0 ?
The solutions to the equation 3x^2+3x-9=0 are x=(-1+sqrt(13))/2 ,x=-(1+sqrt(13))/2
Find the zeros of 3x^2+3x-9=0
The zeros of 3x^2+3x-9=0 are x=(-1+sqrt(13))/2 ,x=-(1+sqrt(13))/2