What are the solutions to the equation x^2+14-x=-10x ?

The solutions to the equation x^2+14-x=-10x are x=-2,x=-7

Find the zeros of x^2+14-x=-10x

The zeros of x^2+14-x=-10x are x=-2,x=-7

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x^{2} + 14 - x = - 10 x

x = - 2, x = - 7

Solution steps

x^{2} + 14 - x = - 10 x

Move

10 x

to the left side

x^{2} + 14 + 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 9 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 14 = 5

x_{1, 2} = \frac{- 9 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 5}{2 \cdot 1}, x_{2} = \frac{- 9 - 5}{2 \cdot 1}

x = \frac{- 9 + 5}{2 \cdot 1} : - 2

x = \frac{- 9 - 5}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 2, x = - 7

x, x^{2} + 8 x - 9 = 0

x, 16 x^{2} - 96 x - 9 y^{2} + 18 y + 135 = 0

2 x^{2} + 5 x + 20 = 0

a^{2} + 3^{2} = 6^{2}

7 x^{2} - 8 x + 2 = 0

What are the solutions to the equation x^2+14-x=-10x ?
The solutions to the equation x^2+14-x=-10x are x=-2,x=-7
Find the zeros of x^2+14-x=-10x
The zeros of x^2+14-x=-10x are x=-2,x=-7