What are the solutions to the equation -x^2-6x+27=0 ?

The solutions to the equation -x^2-6x+27=0 are x=-9,x=3

Find the zeros of -x^2-6x+27=0

The zeros of -x^2-6x+27=0 are x=-9,x=3

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- x^{2} - 6 x + 27 = 0

x = - 9, x = 3

Solution steps

- x^{2} - 6 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) \cdot 27}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) \cdot 27 = 12

x_{1, 2} = \frac{- ( - 6 ) \pm 12}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 12}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 12}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 12}{2 ( - 1 )} : - 9

x = \frac{- ( - 6 ) - 12}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = - 9, x = 3

4 y^{2} - 8 y = 0

4 - 9 x^{2} = 0

r^{2} + 13 r + 42 = 0

x^{2} - 18 x = - 56

x^{2} - 23 x + 3 = 0

What are the solutions to the equation -x^2-6x+27=0 ?
The solutions to the equation -x^2-6x+27=0 are x=-9,x=3
Find the zeros of -x^2-6x+27=0
The zeros of -x^2-6x+27=0 are x=-9,x=3