What are the solutions to the equation x^2-18x=-56 ?

The solutions to the equation x^2-18x=-56 are x=14,x=4

Find the zeros of x^2-18x=-56

The zeros of x^2-18x=-56 are x=14,x=4

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x^{2} - 18 x = - 56

x = 14, x = 4

Solution steps

x^{2} - 18 x = - 56

Move

56

to the left side

x^{2} - 18 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 56 = 10

x_{1, 2} = \frac{- ( - 18 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 10}{2 \cdot 1}

x = \frac{- ( - 18 ) + 10}{2 \cdot 1} : 14

x = \frac{- ( - 18 ) - 10}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 14, x = 4

x^{2} - 23 x + 3 = 0

a, \frac{d ^{3}}{d t ^{3}} ((u) u^{3}) = a^{2} t

0 = - 2 x^{2} + x (3 - 6) - 8

2 n^{2} - 4 n + 2 = 0

6 x^{2} + 11 x = 8

What are the solutions to the equation x^2-18x=-56 ?
The solutions to the equation x^2-18x=-56 are x=14,x=4
Find the zeros of x^2-18x=-56
The zeros of x^2-18x=-56 are x=14,x=4