What are the solutions to the equation 0=-2x^2+x(3-6)-8 ?

The solutions to the equation 0=-2x^2+x(3-6)-8 are x=-3/4-i(sqrt(55))/4 ,x=-3/4+i(sqrt(55))/4

Find the zeros of 0=-2x^2+x(3-6)-8

The zeros of 0=-2x^2+x(3-6)-8 are x=-3/4-i(sqrt(55))/4 ,x=-3/4+i(sqrt(55))/4

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0 = - 2 x^{2} + x (3 - 6) - 8

x = - \frac{3}{4} - i \frac{55}{4}, x = - \frac{3}{4} + i \frac{55}{4}

Solution steps

0 = - 2 x^{2} + x (3 - 6) - 8

Expand

- 2 x^{2} + x (3 - 6) - 8 : - 2 x^{2} - 3 x - 8

0 = - 2 x^{2} - 3 x - 8

Switch sides

- 2 x^{2} - 3 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 2 ) ( - 8 )}{2 ( - 2 )}

Simplify

(- 3)^{2} - 4 (- 2) (- 8) : 55 i

x_{1, 2} = \frac{- ( - 3 ) \pm 55 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 55 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 3 ) - 55 i}{2 ( - 2 )}

x = \frac{- ( - 3 ) + 55 i}{2 ( - 2 )} : - \frac{3}{4} - i \frac{55}{4}

x = \frac{- ( - 3 ) - 55 i}{2 ( - 2 )} : - \frac{3}{4} + i \frac{55}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{4} - i \frac{55}{4}, x = - \frac{3}{4} + i \frac{55}{4}

2 n^{2} - 4 n + 2 = 0

6 x^{2} + 11 x = 8

5 a^{2} - 45 = 0

3 x + 1 = x^{2} - 6 x + 9

- x^{2} + 10 x = 24

What are the solutions to the equation 0=-2x^2+x(3-6)-8 ?
The solutions to the equation 0=-2x^2+x(3-6)-8 are x=-3/4-i(sqrt(55))/4 ,x=-3/4+i(sqrt(55))/4
Find the zeros of 0=-2x^2+x(3-6)-8
The zeros of 0=-2x^2+x(3-6)-8 are x=-3/4-i(sqrt(55))/4 ,x=-3/4+i(sqrt(55))/4