What are the solutions to the equation 6x^2+11x=8 ?

The solutions to the equation 6x^2+11x=8 are x=(-11+sqrt(313))/(12),x=(-11-sqrt(313))/(12)

Find the zeros of 6x^2+11x=8

The zeros of 6x^2+11x=8 are x=(-11+sqrt(313))/(12),x=(-11-sqrt(313))/(12)

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6 x^{2} + 11 x = 8

x = \frac{- 11 + 313}{12}, x = \frac{- 11 - 313}{12}

Decimal Notation

x = 0.55765 \dots, x = - 2.39098 \dots

Solution steps

6 x^{2} + 11 x = 8

Move

8

to the left side

6 x^{2} + 11 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 6 ( - 8 )}{2 \cdot 6}

1 1^{2} - 4 \cdot 6 (- 8) = 313

x_{1, 2} = \frac{- 11 \pm 313}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 11 + 313}{2 \cdot 6}, x_{2} = \frac{- 11 - 313}{2 \cdot 6}

x = \frac{- 11 + 313}{2 \cdot 6} : \frac{- 11 + 313}{12}

x = \frac{- 11 - 313}{2 \cdot 6} : \frac{- 11 - 313}{12}

The solutions to the quadratic equation are:

x = \frac{- 11 + 313}{12}, x = \frac{- 11 - 313}{12}

5 a^{2} - 45 = 0

3 x + 1 = x^{2} - 6 x + 9

- x^{2} + 10 x = 24

x^{2} - 3 x + 2 = 6

x^{2} - 18 x + 81 = 16

What are the solutions to the equation 6x^2+11x=8 ?
The solutions to the equation 6x^2+11x=8 are x=(-11+sqrt(313))/(12),x=(-11-sqrt(313))/(12)
Find the zeros of 6x^2+11x=8
The zeros of 6x^2+11x=8 are x=(-11+sqrt(313))/(12),x=(-11-sqrt(313))/(12)