What are the solutions to the equation x^2-3x+2=6 ?

The solutions to the equation x^2-3x+2=6 are x=4,x=-1

Find the zeros of x^2-3x+2=6

The zeros of x^2-3x+2=6 are x=4,x=-1

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x^{2} - 3 x + 2 = 6

x = 4, x = - 1

Solution steps

x^{2} - 3 x + 2 = 6

Move

6

to the left side

x^{2} - 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 4) = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 1}

x = \frac{- ( - 3 ) + 5}{2 \cdot 1} : 4

x = \frac{- ( - 3 ) - 5}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

x^{2} - 18 x + 81 = 16

9 r (r - 2) = r^{2} + 5

x^{2} + 8 x + 3 = 0

16 x^{2} + 24 x + 5 = 0

y, - 3 y^{2} z - 3 y z^{2} = 21

What are the solutions to the equation x^2-3x+2=6 ?
The solutions to the equation x^2-3x+2=6 are x=4,x=-1
Find the zeros of x^2-3x+2=6
The zeros of x^2-3x+2=6 are x=4,x=-1