What are the solutions to the equation -0.01x^2+50x+300=0 ?

The solutions to the equation -0.01x^2+50x+300=0 are x=-100(2sqrt(157)-25),x=100(25+2sqrt(157))

Find the zeros of -0.01x^2+50x+300=0

The zeros of -0.01x^2+50x+300=0 are x=-100(2sqrt(157)-25),x=100(25+2sqrt(157))

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- 0.01 x^{2} + 50 x + 300 = 0

x = - 100 (2157 - 25), x = 100 (25 + 2157)

Decimal Notation

x = - 5.99281 \dots, x = 5005.99281 \dots

Solution steps

- 0.01 x^{2} + 50 x + 300 = 0

Multiply both sides by

100

- x^{2} + 5000 x + 30000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5000 \pm 500 0 ^{2} - 4 ( - 1 ) \cdot 30000}{2 ( - 1 )}

500 0^{2} - 4 (- 1) \cdot 30000 = 400157

x_{1, 2} = \frac{- 5000 \pm 400 157}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5000 + 400 157}{2 ( - 1 )}, x_{2} = \frac{- 5000 - 400 157}{2 ( - 1 )}

x = \frac{- 5000 + 400 157}{2 ( - 1 )} : - 100 (2157 - 25)

x = \frac{- 5000 - 400 157}{2 ( - 1 )} : 100 (25 + 2157)

The solutions to the quadratic equation are:

x = - 100 (2157 - 25), x = 100 (25 + 2157)

(x - 2) (3 x + 1) = 0

n^{2} - 11 n + 24 = 0

a = 6 a^{2}

0 = x^{2} - 11 x + 24

- 8 x^{2} - 14 x + 15 = 0

What are the solutions to the equation -0.01x^2+50x+300=0 ?
The solutions to the equation -0.01x^2+50x+300=0 are x=-100(2sqrt(157)-25),x=100(25+2sqrt(157))
Find the zeros of -0.01x^2+50x+300=0
The zeros of -0.01x^2+50x+300=0 are x=-100(2sqrt(157)-25),x=100(25+2sqrt(157))