What are the solutions to the equation (x-2)(3x+1)=0 ?

The solutions to the equation (x-2)(3x+1)=0 are x=2,x=-1/3

Find the zeros of (x-2)(3x+1)=0

The zeros of (x-2)(3x+1)=0 are x=2,x=-1/3

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(x - 2) (3 x + 1) = 0

x = 2, x = - \frac{1}{3}

Decimal Notation

x = 2, x = - 0.33333 \dots

Solution steps

(x - 2) (3 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 3 x + 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{3}

n^{2} - 11 n + 24 = 0

a = 6 a^{2}

0 = x^{2} - 11 x + 24

- 8 x^{2} - 14 x + 15 = 0

- 3 x^{2} + 3 x + 60 = 0

What are the solutions to the equation (x-2)(3x+1)=0 ?
The solutions to the equation (x-2)(3x+1)=0 are x=2,x=-1/3
Find the zeros of (x-2)(3x+1)=0
The zeros of (x-2)(3x+1)=0 are x=2,x=-1/3