What are the solutions to the equation t^2+4=0 ?

The solutions to the equation t^2+4=0 are t=2i,t=-2i

Find the zeros of t^2+4=0

The zeros of t^2+4=0 are t=2i,t=-2i

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t^{2} + 4 = 0

t = 2 i, t = - 2 i

Solution steps

t^{2} + 4 = 0

Move

4

to the right side

t^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = - 4, t = - - 4

- 4 = 2 i

- - 4 = - 2 i

t = 2 i, t = - 2 i

(m - 1)^{2} = 0

4 x^{2} + 21 x - 18 = 0

x, x^{2} = - 1

- 9 x^{2} + x = 0

0 = x^{2} + 2 x + 6

What are the solutions to the equation t^2+4=0 ?
The solutions to the equation t^2+4=0 are t=2i,t=-2i
Find the zeros of t^2+4=0
The zeros of t^2+4=0 are t=2i,t=-2i