What are the solutions to the equation -9x^2+x=0 ?

The solutions to the equation -9x^2+x=0 are x=0,x= 1/9

Find the zeros of -9x^2+x=0

The zeros of -9x^2+x=0 are x=0,x= 1/9

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- 9 x^{2} + x = 0

x = 0, x = \frac{1}{9}

Decimal Notation

x = 0, x = 0.11111 \dots

Solution steps

- 9 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 9 ) \cdot 0}{2 ( - 9 )}

1^{2} - 4 (- 9) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 9 )}, x_{2} = \frac{- 1 - 1}{2 ( - 9 )}

x = \frac{- 1 + 1}{2 ( - 9 )} : 0

x = \frac{- 1 - 1}{2 ( - 9 )} : \frac{1}{9}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{9}

0 = x^{2} + 2 x + 6

0 = x^{2} + 2 x - 6

x^{2} - 10 x - 10 = 0

2 x^{2} - 24 = 8 x

What are the solutions to the equation -9x^2+x=0 ?
The solutions to the equation -9x^2+x=0 are x=0,x= 1/9
Find the zeros of -9x^2+x=0
The zeros of -9x^2+x=0 are x=0,x= 1/9