What are the solutions to the equation 0=x^2+2x-6 ?

The solutions to the equation 0=x^2+2x-6 are x=-1+sqrt(7),x=-1-sqrt(7)

Find the zeros of 0=x^2+2x-6

The zeros of 0=x^2+2x-6 are x=-1+sqrt(7),x=-1-sqrt(7)

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0 = x^{2} + 2 x - 6

x = - 1 + 7, x = - 1 - 7

Decimal Notation

x = 1.64575 \dots, x = - 3.64575 \dots

Solution steps

0 = x^{2} + 2 x - 6

Switch sides

x^{2} + 2 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 6) = 27

x_{1, 2} = \frac{- 2 \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 7}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 7}{2 \cdot 1}

x = \frac{- 2 + 2 7}{2 \cdot 1} : - 1 + 7

x = \frac{- 2 - 2 7}{2 \cdot 1} : - 1 - 7

The solutions to the quadratic equation are:

x = - 1 + 7, x = - 1 - 7

x^{2} - 10 x - 10 = 0

2 x^{2} - 24 = 8 x

4 x^{2} - 24 x + 35 = 0

t^{2} + 2 = 0

2 x^{2} - x + 55 = x^{2} + 10 x + 25

What are the solutions to the equation 0=x^2+2x-6 ?
The solutions to the equation 0=x^2+2x-6 are x=-1+sqrt(7),x=-1-sqrt(7)
Find the zeros of 0=x^2+2x-6
The zeros of 0=x^2+2x-6 are x=-1+sqrt(7),x=-1-sqrt(7)