What are the solutions to the equation 7x^2+21x=28 ?

The solutions to the equation 7x^2+21x=28 are x=1,x=-4

Find the zeros of 7x^2+21x=28

The zeros of 7x^2+21x=28 are x=1,x=-4

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7 x^{2} + 21 x = 28

x = 1, x = - 4

Solution steps

7 x^{2} + 21 x = 28

Move

28

to the left side

7 x^{2} + 21 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 7 ( - 28 )}{2 \cdot 7}

2 1^{2} - 4 \cdot 7 (- 28) = 35

x_{1, 2} = \frac{- 21 \pm 35}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 21 + 35}{2 \cdot 7}, x_{2} = \frac{- 21 - 35}{2 \cdot 7}

x = \frac{- 21 + 35}{2 \cdot 7} : 1

x = \frac{- 21 - 35}{2 \cdot 7} : - 4

The solutions to the quadratic equation are:

x = 1, x = - 4

x^{2} + 100 = 29 x

y^{2} + 3 y = 6 y + 10

4 x^{2} + 6 x + 8 = 0

3 x^{2} - 6 x = 5

x^{2} - 6 x - 5 = 2

What are the solutions to the equation 7x^2+21x=28 ?
The solutions to the equation 7x^2+21x=28 are x=1,x=-4
Find the zeros of 7x^2+21x=28
The zeros of 7x^2+21x=28 are x=1,x=-4