What are the solutions to the equation x(x+2)=143 ?

The solutions to the equation x(x+2)=143 are x=11,x=-13

Find the zeros of x(x+2)=143

The zeros of x(x+2)=143 are x=11,x=-13

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x (x + 2) = 143

x = 11, x = - 13

Solution steps

x (x + 2) = 143

Expand

x (x + 2) : x^{2} + 2 x

x^{2} + 2 x = 143

Move

143

to the left side

x^{2} + 2 x - 143 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 143 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 143) = 24

x_{1, 2} = \frac{- 2 \pm 24}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 24}{2 \cdot 1}, x_{2} = \frac{- 2 - 24}{2 \cdot 1}

x = \frac{- 2 + 24}{2 \cdot 1} : 11

x = \frac{- 2 - 24}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 11, x = - 13

9 x^{2} + 24 x + 19 = 0

4 x^{2} + 10 x - 3 = 0

t, d = 4.9 t^{2}

u^{2} - 6 u + 9 = 0

x (x - 5) = - 6

What are the solutions to the equation x(x+2)=143 ?
The solutions to the equation x(x+2)=143 are x=11,x=-13
Find the zeros of x(x+2)=143
The zeros of x(x+2)=143 are x=11,x=-13