What are the solutions to the equation u^2-6u+9=0 ?

The solutions to the equation u^2-6u+9=0 are u=3

Find the zeros of u^2-6u+9=0

The zeros of u^2-6u+9=0 are u=3

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u^{2} - 6 u + 9 = 0

u = 3

Solution steps

u^{2} - 6 u + 9 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

u_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

u = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

u = 3

The solution to the quadratic equation is:

u = 3

x (x - 5) = - 6

x^{2} + 17 x + 3 = 0

d, A = \frac{1}{2} d^{2}

132 - 92 x + 12 x^{2} = 0

- 2 x^{2} - 2 x - 3 = 0

What are the solutions to the equation u^2-6u+9=0 ?
The solutions to the equation u^2-6u+9=0 are u=3
Find the zeros of u^2-6u+9=0
The zeros of u^2-6u+9=0 are u=3