What are the solutions to the equation 5y^2-6y-3=0 ?

The solutions to the equation 5y^2-6y-3=0 are y=(3+2sqrt(6))/5 ,y=(3-2sqrt(6))/5

Find the zeros of 5y^2-6y-3=0

The zeros of 5y^2-6y-3=0 are y=(3+2sqrt(6))/5 ,y=(3-2sqrt(6))/5

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5 y^{2} - 6 y - 3 = 0

y = \frac{3 + 2 6}{5}, y = \frac{3 - 2 6}{5}

Decimal Notation

y = 1.57979 \dots, y = - 0.37979 \dots

Solution steps

5 y^{2} - 6 y - 3 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

(- 6)^{2} - 4 \cdot 5 (- 3) = 46

y_{1, 2} = \frac{- ( - 6 ) \pm 4 6}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 4 6}{2 \cdot 5}, y_{2} = \frac{- ( - 6 ) - 4 6}{2 \cdot 5}

y = \frac{- ( - 6 ) + 4 6}{2 \cdot 5} : \frac{3 + 2 6}{5}

y = \frac{- ( - 6 ) - 4 6}{2 \cdot 5} : \frac{3 - 2 6}{5}

The solutions to the quadratic equation are:

y = \frac{3 + 2 6}{5}, y = \frac{3 - 2 6}{5}

a^{2} - 5 a + 2 = 0

2 0^{2} = 1 2^{2} + x^{2}

2 y^{2} - 8 y + 7 = 0

x, x^{2} + y^{2} = - 4

x^{2} + 6 x + 10 = 0

What are the solutions to the equation 5y^2-6y-3=0 ?
The solutions to the equation 5y^2-6y-3=0 are y=(3+2sqrt(6))/5 ,y=(3-2sqrt(6))/5
Find the zeros of 5y^2-6y-3=0
The zeros of 5y^2-6y-3=0 are y=(3+2sqrt(6))/5 ,y=(3-2sqrt(6))/5