What are the solutions to the equation G(x)=-2x^2+80x ?

The solutions to the equation G(x)=-2x^2+80x are x=0,x=(80-G)/2

Find the zeros of G(x)=-2x^2+80x

The zeros of G(x)=-2x^2+80x are x=0,x=(80-G)/2

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G (x) = - 2 x^{2} + 80 x

x = 0, x = \frac{80 - G}{2}

Solution steps

G (x) = - 2 x^{2} + 80 x

Refine

G x = - 2 x^{2} + 80 x

Switch sides

- 2 x^{2} + 80 x = G x

Move

G x

to the left side

- 2 x^{2} + 80 x - G x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + (80 - G) x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 80 - G ) \pm ( 80 - G ) ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

Simplify

(80 - G)^{2} - 4 (- 2) \cdot 0 : - G + 80

x_{1, 2} = \frac{- ( 80 - G ) \pm ( - G + 80 )}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( 80 - G ) - G + 80}{2 ( - 2 )}, x_{2} = \frac{- ( 80 - G ) - ( - G + 80 )}{2 ( - 2 )}

x = \frac{- ( 80 - G ) - G + 80}{2 ( - 2 )} : 0

x = \frac{- ( 80 - G ) - ( - G + 80 )}{2 ( - 2 )} : \frac{80 - G}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{80 - G}{2}

0 = x^{2} + 12 x + 11

12 x^{2} - 368 x + 1891 = 0

v^{2} = 18 v

x, z = x^{2} y

2 y^{2} + y - 6 = 0

What are the solutions to the equation G(x)=-2x^2+80x ?
The solutions to the equation G(x)=-2x^2+80x are x=0,x=(80-G)/2
Find the zeros of G(x)=-2x^2+80x
The zeros of G(x)=-2x^2+80x are x=0,x=(80-G)/2