What are the solutions to the equation 0=x^2+12x+11 ?

The solutions to the equation 0=x^2+12x+11 are x=-1,x=-11

Find the zeros of 0=x^2+12x+11

The zeros of 0=x^2+12x+11 are x=-1,x=-11

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0 = x^{2} + 12 x + 11

x = - 1, x = - 11

Solution steps

0 = x^{2} + 12 x + 11

Switch sides

x^{2} + 12 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 11 = 10

x_{1, 2} = \frac{- 12 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 10}{2 \cdot 1}, x_{2} = \frac{- 12 - 10}{2 \cdot 1}

x = \frac{- 12 + 10}{2 \cdot 1} : - 1

x = \frac{- 12 - 10}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = - 1, x = - 11

12 x^{2} - 368 x + 1891 = 0

v^{2} = 18 v

x, z = x^{2} y

2 y^{2} + y - 6 = 0

b^{2} - 16 b + 64 = 0

What are the solutions to the equation 0=x^2+12x+11 ?
The solutions to the equation 0=x^2+12x+11 are x=-1,x=-11
Find the zeros of 0=x^2+12x+11
The zeros of 0=x^2+12x+11 are x=-1,x=-11