What are the solutions to the equation x^2+10x+25=49 ?

The solutions to the equation x^2+10x+25=49 are x=2,x=-12

Find the zeros of x^2+10x+25=49

The zeros of x^2+10x+25=49 are x=2,x=-12

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x^{2} + 10 x + 25 = 49

x = 2, x = - 12

Solution steps

x^{2} + 10 x + 25 = 49

Move

49

to the left side

x^{2} + 10 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 24) = 14

x_{1, 2} = \frac{- 10 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 14}{2 \cdot 1}, x_{2} = \frac{- 10 - 14}{2 \cdot 1}

x = \frac{- 10 + 14}{2 \cdot 1} : 2

x = \frac{- 10 - 14}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 2, x = - 12

\frac{7}{2} x^{2} + 3 x + \frac{8}{3}

27 - \frac{3}{4} x^{2} = 0

- 5 x - 2 = - 3 x^{2}

X^{2} + 8 X + 15 = 0

2 X^{2} + 11 X + 5 = 0

What are the solutions to the equation x^2+10x+25=49 ?
The solutions to the equation x^2+10x+25=49 are x=2,x=-12
Find the zeros of x^2+10x+25=49
The zeros of x^2+10x+25=49 are x=2,x=-12