What are the solutions to the equation X^2+8X+15=0 ?

The solutions to the equation X^2+8X+15=0 are X=-3,X=-5

Find the zeros of X^2+8X+15=0

The zeros of X^2+8X+15=0 are X=-3,X=-5

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X^{2} + 8 X + 15 = 0

X = - 3, X = - 5

Solution steps

X^{2} + 8 X + 15 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 15 = 2

X_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 8 + 2}{2 \cdot 1}, X_{2} = \frac{- 8 - 2}{2 \cdot 1}

X = \frac{- 8 + 2}{2 \cdot 1} : - 3

X = \frac{- 8 - 2}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

X = - 3, X = - 5

2 X^{2} + 11 X + 5 = 0

2 x^{2} + 6 x + 18 = 0

k^{2} - 9 k + 8 = 0

0 = 3 x^{2} - 10 x - 8

3 x^{2} - 10 x - 3 = 0

What are the solutions to the equation X^2+8X+15=0 ?
The solutions to the equation X^2+8X+15=0 are X=-3,X=-5
Find the zeros of X^2+8X+15=0
The zeros of X^2+8X+15=0 are X=-3,X=-5