What are the solutions to the equation 2x^2+3x=8x+3 ?

The solutions to the equation 2x^2+3x=8x+3 are x=3,x=-1/2

Find the zeros of 2x^2+3x=8x+3

The zeros of 2x^2+3x=8x+3 are x=3,x=-1/2

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2 x^{2} + 3 x = 8 x + 3

x = 3, x = - \frac{1}{2}

Decimal Notation

x = 3, x = - 0.5

Solution steps

2 x^{2} + 3 x = 8 x + 3

Move

3

to the left side

2 x^{2} + 3 x - 3 = 8 x

Move

8 x

to the left side

2 x^{2} - 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 3) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 2}

x = \frac{- ( - 5 ) + 7}{2 \cdot 2} : 3

x = \frac{- ( - 5 ) - 7}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{2}

a, a^{2} b - b^{3} = (2 ab - 2 b^{2})

- 3 d^{2} - 4 d + 5 = 0

25 r^{2} + 7 = 107

6 x^{2} + 5 x + 8 = 0

a, (a + b)^{3} = a^{3} + b^{3}

What are the solutions to the equation 2x^2+3x=8x+3 ?
The solutions to the equation 2x^2+3x=8x+3 are x=3,x=-1/2
Find the zeros of 2x^2+3x=8x+3
The zeros of 2x^2+3x=8x+3 are x=3,x=-1/2