What are the solutions to the equation 4x^2+10x-1.55=0 ?

The solutions to the equation 4x^2+10x-1.55=0 are x=(-25+2sqrt(195))/(20),x=-(25+2sqrt(195))/(20)

Find the zeros of 4x^2+10x-1.55=0

The zeros of 4x^2+10x-1.55=0 are x=(-25+2sqrt(195))/(20),x=-(25+2sqrt(195))/(20)

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4 x^{2} + 10 x - 1.55 = 0

x = \frac{- 25 + 2 195}{20}, x = - \frac{25 + 2 195}{20}

Decimal

x = 0.14642 \dots, x = - 2.64642 \dots

Solution steps

4 x^{2} + 10 x - 1.55 = 0

Multiply both sides by

100

400 x^{2} + 1000 x - 155 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1000 \pm 100 0 ^{2} - 4 \cdot 400 ( - 155 )}{2 \cdot 400}

100 0^{2} - 4 \cdot 400 (- 155) = 80195

x_{1, 2} = \frac{- 1000 \pm 80 195}{2 \cdot 400}

Separate the solutions

x_{1} = \frac{- 1000 + 80 195}{2 \cdot 400}, x_{2} = \frac{- 1000 - 80 195}{2 \cdot 400}

x = \frac{- 1000 + 80 195}{2 \cdot 400} : \frac{- 25 + 2 195}{20}

x = \frac{- 1000 - 80 195}{2 \cdot 400} : - \frac{25 + 2 195}{20}

The solutions to the quadratic equation are:

x = \frac{- 25 + 2 195}{20}, x = - \frac{25 + 2 195}{20}

t^{2} - 3 = 0

\frac{1}{2} x^{2} - 4 x - 5 = 0

x, x^{2} + y^{2} + z^{2} - 2 y = 8

(x^{2} - 6) 2 = - 3 x^{2} + 18

x, 5 x y - 3 x^{2} = 2 y^{2}

What are the solutions to the equation 4x^2+10x-1.55=0 ?
The solutions to the equation 4x^2+10x-1.55=0 are x=(-25+2sqrt(195))/(20),x=-(25+2sqrt(195))/(20)
Find the zeros of 4x^2+10x-1.55=0
The zeros of 4x^2+10x-1.55=0 are x=(-25+2sqrt(195))/(20),x=-(25+2sqrt(195))/(20)