What are the solutions to the equation 1/2 x^2-4x-5=0 ?

The solutions to the equation 1/2 x^2-4x-5=0 are x=4+sqrt(26),x=4-sqrt(26)

Find the zeros of 1/2 x^2-4x-5=0

The zeros of 1/2 x^2-4x-5=0 are x=4+sqrt(26),x=4-sqrt(26)

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\frac{1}{2} x^{2} - 4 x - 5 = 0

x = 4 + 26, x = 4 - 26

Decimal

x = 9.09901 \dots, x = - 1.09901 \dots

Solution steps

\frac{1}{2} x^{2} - 4 x - 5 = 0

Multiply both sides by

2

x^{2} - 8 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 10) = 226

x_{1, 2} = \frac{- ( - 8 ) \pm 2 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 26}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 26}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 26}{2 \cdot 1} : 4 + 26

x = \frac{- ( - 8 ) - 2 26}{2 \cdot 1} : 4 - 26

The solutions to the quadratic equation are:

x = 4 + 26, x = 4 - 26

x, x^{2} + y^{2} + z^{2} - 2 y = 8

(x^{2} - 6) 2 = - 3 x^{2} + 18

x, 5 x y - 3 x^{2} = 2 y^{2}

x^{2} + 2^{2} = 4^{2}

2 x^{2} - 5 x + 2 = 1

What are the solutions to the equation 1/2 x^2-4x-5=0 ?
The solutions to the equation 1/2 x^2-4x-5=0 are x=4+sqrt(26),x=4-sqrt(26)
Find the zeros of 1/2 x^2-4x-5=0
The zeros of 1/2 x^2-4x-5=0 are x=4+sqrt(26),x=4-sqrt(26)